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15c^2+37c+18=0
a = 15; b = 37; c = +18;
Δ = b2-4ac
Δ = 372-4·15·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-17}{2*15}=\frac{-54}{30} =-1+4/5 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+17}{2*15}=\frac{-20}{30} =-2/3 $
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